Pulse Energy & Peak Power

Convert between average power, repetition rate, and pulse energy, then get the peak power, duty cycle, and peak-to-average ratio. Peak power uses the correct factor for rectangular, Gaussian, or sech² pulses.

Inputs

Q-switched ns pulses are usually close to Gaussian. Soliton mode-locked fs/ps pulses are close to sech².

Results

Peak powerPpeak—
Pulse energyEp—
Average powerPavg—
Repetition ratefrep—
Pulse period1/frep—
Duty cycleτ·frep—
Peak-to-average power ratio—
Rectangular estimate Ep/τ—

How it is calculated

The pulse energy, average power, and repetition rate are linked by

\[ E_p = \frac{P_\text{avg}}{f_\text{rep}}, \qquad D = \tau\, f_\text{rep}, \qquad \frac{P_\text{peak}}{P_\text{avg}} = \frac{k}{\tau f_\text{rep}} . \]

The peak power depends on how the energy is distributed in time. For a pulse of full width at half maximum \(\tau\),

\[ P_\text{peak} = k\,\frac{E_p}{\tau}, \qquad k = \begin{cases} 1 & \text{rectangular} \\ 2\sqrt{\ln 2/\pi} \approx 0.9394 & \text{Gaussian} \\ \ln\!\left(1+\sqrt{2}\right) \approx 0.8814 & \operatorname{sech}^2 \end{cases} \]

The factor \(k\) is the ratio of the FWHM to the pulse's energy-equivalent width. A Gaussian's integral is \(1.0645\,P_\text{peak}\tau\). A sech² pulse has longer wings, and its integral is \(1.1346\,P_\text{peak}\tau\).

Smooth pulses have lower peaks, not higher

With the energy and FWHM fixed, the rectangular estimate \(E_p/\tau\) overestimates the true peak power, by 6.4 % for a Gaussian pulse and 13.5 % for sech². Smooth pulses spread some energy into wings outside the FWHM, so less is left for the peak. Factor-of-two differences in peak irradiance come from the beam's spatial profile: a Gaussian beam's on-axis fluence is twice the energy divided by the 1/e² area. The fluence and irradiance tool handles that.

Shapek = Ppeakτ/Ep∫P dt / (Ppeakτ)Autocorrelation FWHM / τ
Rectangular11—
Gaussian0.93941.06451.414
sech²0.88141.13461.543

The last column matters for ultrafast lasers. An intensity autocorrelator reports a width longer than the pulse, so divide by the deconvolution factor before using the duration here.

Worked examples

Q-switched fiber laser. 20 W average at 100 kHz with 10 ns Gaussian pulses:

\[ E_p = \frac{20\ \text{W}}{100\ \text{kHz}} = 200\ \mu\text{J}, \qquad P_\text{peak} = 0.9394\times\frac{200\ \mu\text{J}}{10\ \text{ns}} \approx 18.8\ \text{kW}. \]

The duty cycle is 0.1 %, so the peak power is about 940 times the average.

Ultrafast laser. 10 W at 1 MHz with 300 fs sech² pulses gives \(E_p = 10\ \mu\)J and \(P_\text{peak} = 0.8814 \times 10\ \mu\text{J}/300\ \text{fs} \approx 29\ \text{MW}\). The average power is modest, but the peak power is about three million times higher.

Assumptions and limits

References

  1. A. E. Siegman, Lasers, University Science Books (1986), ch. 9 (pulse shapes and widths).
  2. J.-C. Diels and W. Rudolph, Ultrashort Laser Pulse Phenomena, 2nd ed., Academic Press (2006), ch. 9 (autocorrelation deconvolution factors).